This is a step-by-step verification of the answer by our certified professional. Now simply convert one hundred twenty Minutes into hours by dividing one hundred twenty by 2. Doubtnut just isn’t answerable for any discrepancies regarding the duplicity of content over these questions. For unlimited access to Homework Help, a Homework+ subscription is required.

A automotive travels at a velocity of 50 m/sec. What is the distance travelled by the automobile… A automobile takes four hours to reach the vacation spot by travelling at a speed of 60 km/h . A car takes 2 hours to reach a vacation spot by travelling on the velocity of 60 km/hr.How long it take w… A car travels a distance of one hundred fifty km in three hours and a practice travels a distance of a hundred and twenty km in 2 hours. The acceleration of the car is0 m/s² because it travels at a continuing speed.

Need a deep-dive on the idea behind this application? Learn more about this matter, chemistry and related others by exploring similar questions and additional content under. An electron travels with velocity 2.zero × 107 m/s between the 2 parallel charged plates proven…

A automobile travels first 60km at a speed of 3v km/hr and travels next om at 2v km/hr. Traveling at a speed of 60 km/h, it takes 2 hours to succeed in by a automobile. How lengthy will it take when the … A automotive travels a hundred and forty km partly at a speed of 6 km/h and the remaining at a pace of 10 km/h. A automobile is travelling 60 km in 2 h, then the space travelled by the automobile in 6 h, if the speed stay… This boundary or distance is identified as the circumference of the circular playground.

Speed of car is 36 km/h and … The african cicada is the world’s loudest insect, producing a sound depth degree of 107 db at a distance of zero for which compound does 0.256 mole weigh 12.8 g.50 m. What is the depth of its sound (in w/m2) as heard by somebody standing three.1 m away? Express your reply in watts per meter squared.

An electron at level A in the determine has a pace of 1.42×10∧6 m/s. Find the course of the magnetic subject that can cause the electron to observe the semicircular path from A to B. Find the magnitude of the magnetic area that will cause the electron to observe the semicircular path from A to B. Find the time required for the electron to maneuver from A to B. Find the direction of the magnetic subject, that… Firstly you should convert those 7200 Seconds into minutes.

Then we get the speed of the automobile in middles post second, there’s 20.eight m/s. If you want to study A automotive traveling with constant speed travels 150 km in 7200 s . A automotive touring with fixed pace travels one hundred fifty km in 7200 s.